Integrand size = 24, antiderivative size = 115 \[ \int \frac {\sin ^3(c+d x)}{a-b \sin ^4(c+d x)} \, dx=-\frac {\arctan \left (\frac {\sqrt [4]{b} \cos (c+d x)}{\sqrt {\sqrt {a}-\sqrt {b}}}\right )}{2 \sqrt {\sqrt {a}-\sqrt {b}} b^{3/4} d}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{b} \cos (c+d x)}{\sqrt {\sqrt {a}+\sqrt {b}}}\right )}{2 \sqrt {\sqrt {a}+\sqrt {b}} b^{3/4} d} \]
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Time = 0.07 (sec) , antiderivative size = 115, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {3294, 1180, 211, 214} \[ \int \frac {\sin ^3(c+d x)}{a-b \sin ^4(c+d x)} \, dx=\frac {\text {arctanh}\left (\frac {\sqrt [4]{b} \cos (c+d x)}{\sqrt {\sqrt {a}+\sqrt {b}}}\right )}{2 b^{3/4} d \sqrt {\sqrt {a}+\sqrt {b}}}-\frac {\arctan \left (\frac {\sqrt [4]{b} \cos (c+d x)}{\sqrt {\sqrt {a}-\sqrt {b}}}\right )}{2 b^{3/4} d \sqrt {\sqrt {a}-\sqrt {b}}} \]
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Rule 211
Rule 214
Rule 1180
Rule 3294
Rubi steps \begin{align*} \text {integral}& = -\frac {\text {Subst}\left (\int \frac {1-x^2}{a-b+2 b x^2-b x^4} \, dx,x,\cos (c+d x)\right )}{d} \\ & = \frac {\text {Subst}\left (\int \frac {1}{-\sqrt {a} \sqrt {b}+b-b x^2} \, dx,x,\cos (c+d x)\right )}{2 d}+\frac {\text {Subst}\left (\int \frac {1}{\sqrt {a} \sqrt {b}+b-b x^2} \, dx,x,\cos (c+d x)\right )}{2 d} \\ & = -\frac {\arctan \left (\frac {\sqrt [4]{b} \cos (c+d x)}{\sqrt {\sqrt {a}-\sqrt {b}}}\right )}{2 \sqrt {\sqrt {a}-\sqrt {b}} b^{3/4} d}+\frac {\text {arctanh}\left (\frac {\sqrt [4]{b} \cos (c+d x)}{\sqrt {\sqrt {a}+\sqrt {b}}}\right )}{2 \sqrt {\sqrt {a}+\sqrt {b}} b^{3/4} d} \\ \end{align*}
Result contains higher order function than in optimal. Order 9 vs. order 3 in optimal.
Time = 3.61 (sec) , antiderivative size = 285, normalized size of antiderivative = 2.48 \[ \int \frac {\sin ^3(c+d x)}{a-b \sin ^4(c+d x)} \, dx=-\frac {i \text {RootSum}\left [b-4 b \text {$\#$1}^2-16 a \text {$\#$1}^4+6 b \text {$\#$1}^4-4 b \text {$\#$1}^6+b \text {$\#$1}^8\&,\frac {-2 \arctan \left (\frac {\sin (c+d x)}{\cos (c+d x)-\text {$\#$1}}\right )+i \log \left (1-2 \cos (c+d x) \text {$\#$1}+\text {$\#$1}^2\right )+6 \arctan \left (\frac {\sin (c+d x)}{\cos (c+d x)-\text {$\#$1}}\right ) \text {$\#$1}^2-3 i \log \left (1-2 \cos (c+d x) \text {$\#$1}+\text {$\#$1}^2\right ) \text {$\#$1}^2-6 \arctan \left (\frac {\sin (c+d x)}{\cos (c+d x)-\text {$\#$1}}\right ) \text {$\#$1}^4+3 i \log \left (1-2 \cos (c+d x) \text {$\#$1}+\text {$\#$1}^2\right ) \text {$\#$1}^4+2 \arctan \left (\frac {\sin (c+d x)}{\cos (c+d x)-\text {$\#$1}}\right ) \text {$\#$1}^6-i \log \left (1-2 \cos (c+d x) \text {$\#$1}+\text {$\#$1}^2\right ) \text {$\#$1}^6}{-b \text {$\#$1}-8 a \text {$\#$1}^3+3 b \text {$\#$1}^3-3 b \text {$\#$1}^5+b \text {$\#$1}^7}\&\right ]}{8 d} \]
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Time = 0.79 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.72
method | result | size |
derivativedivides | \(\frac {b \left (-\frac {\arctan \left (\frac {\cos \left (d x +c \right ) b}{\sqrt {\left (\sqrt {a b}-b \right ) b}}\right )}{2 b \sqrt {\left (\sqrt {a b}-b \right ) b}}+\frac {\operatorname {arctanh}\left (\frac {\cos \left (d x +c \right ) b}{\sqrt {\left (\sqrt {a b}+b \right ) b}}\right )}{2 b \sqrt {\left (\sqrt {a b}+b \right ) b}}\right )}{d}\) | \(83\) |
default | \(\frac {b \left (-\frac {\arctan \left (\frac {\cos \left (d x +c \right ) b}{\sqrt {\left (\sqrt {a b}-b \right ) b}}\right )}{2 b \sqrt {\left (\sqrt {a b}-b \right ) b}}+\frac {\operatorname {arctanh}\left (\frac {\cos \left (d x +c \right ) b}{\sqrt {\left (\sqrt {a b}+b \right ) b}}\right )}{2 b \sqrt {\left (\sqrt {a b}+b \right ) b}}\right )}{d}\) | \(83\) |
risch | \(\frac {i \left (\munderset {\textit {\_R} =\operatorname {RootOf}\left (-16+\left (a \,b^{3} d^{4}-b^{4} d^{4}\right ) \textit {\_Z}^{4}-8 b^{2} d^{2} \textit {\_Z}^{2}\right )}{\sum }\textit {\_R} \ln \left ({\mathrm e}^{2 i \left (d x +c \right )}+\left (\left (-\frac {1}{4} i a \,b^{2} d^{3}+\frac {1}{4} i b^{3} d^{3}\right ) \textit {\_R}^{3}+2 i d b \textit {\_R} \right ) {\mathrm e}^{i \left (d x +c \right )}+1\right )\right )}{8}\) | \(97\) |
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Leaf count of result is larger than twice the leaf count of optimal. 703 vs. \(2 (79) = 158\).
Time = 0.33 (sec) , antiderivative size = 703, normalized size of antiderivative = 6.11 \[ \int \frac {\sin ^3(c+d x)}{a-b \sin ^4(c+d x)} \, dx=\frac {1}{4} \, \sqrt {-\frac {{\left (a b - b^{2}\right )} d^{2} \sqrt {\frac {a}{{\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5}\right )} d^{4}}} + 1}{{\left (a b - b^{2}\right )} d^{2}}} \log \left (-{\left ({\left (a b^{2} - b^{3}\right )} d^{3} \sqrt {\frac {a}{{\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5}\right )} d^{4}}} - b d\right )} \sqrt {-\frac {{\left (a b - b^{2}\right )} d^{2} \sqrt {\frac {a}{{\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5}\right )} d^{4}}} + 1}{{\left (a b - b^{2}\right )} d^{2}}} + \cos \left (d x + c\right )\right ) - \frac {1}{4} \, \sqrt {-\frac {{\left (a b - b^{2}\right )} d^{2} \sqrt {\frac {a}{{\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5}\right )} d^{4}}} + 1}{{\left (a b - b^{2}\right )} d^{2}}} \log \left (-{\left ({\left (a b^{2} - b^{3}\right )} d^{3} \sqrt {\frac {a}{{\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5}\right )} d^{4}}} - b d\right )} \sqrt {-\frac {{\left (a b - b^{2}\right )} d^{2} \sqrt {\frac {a}{{\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5}\right )} d^{4}}} + 1}{{\left (a b - b^{2}\right )} d^{2}}} - \cos \left (d x + c\right )\right ) - \frac {1}{4} \, \sqrt {\frac {{\left (a b - b^{2}\right )} d^{2} \sqrt {\frac {a}{{\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5}\right )} d^{4}}} - 1}{{\left (a b - b^{2}\right )} d^{2}}} \log \left (-{\left ({\left (a b^{2} - b^{3}\right )} d^{3} \sqrt {\frac {a}{{\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5}\right )} d^{4}}} + b d\right )} \sqrt {\frac {{\left (a b - b^{2}\right )} d^{2} \sqrt {\frac {a}{{\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5}\right )} d^{4}}} - 1}{{\left (a b - b^{2}\right )} d^{2}}} + \cos \left (d x + c\right )\right ) + \frac {1}{4} \, \sqrt {\frac {{\left (a b - b^{2}\right )} d^{2} \sqrt {\frac {a}{{\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5}\right )} d^{4}}} - 1}{{\left (a b - b^{2}\right )} d^{2}}} \log \left (-{\left ({\left (a b^{2} - b^{3}\right )} d^{3} \sqrt {\frac {a}{{\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5}\right )} d^{4}}} + b d\right )} \sqrt {\frac {{\left (a b - b^{2}\right )} d^{2} \sqrt {\frac {a}{{\left (a^{2} b^{3} - 2 \, a b^{4} + b^{5}\right )} d^{4}}} - 1}{{\left (a b - b^{2}\right )} d^{2}}} - \cos \left (d x + c\right )\right ) \]
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Timed out. \[ \int \frac {\sin ^3(c+d x)}{a-b \sin ^4(c+d x)} \, dx=\text {Timed out} \]
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\[ \int \frac {\sin ^3(c+d x)}{a-b \sin ^4(c+d x)} \, dx=\int { -\frac {\sin \left (d x + c\right )^{3}}{b \sin \left (d x + c\right )^{4} - a} \,d x } \]
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Leaf count of result is larger than twice the leaf count of optimal. 166 vs. \(2 (79) = 158\).
Time = 0.75 (sec) , antiderivative size = 166, normalized size of antiderivative = 1.44 \[ \int \frac {\sin ^3(c+d x)}{a-b \sin ^4(c+d x)} \, dx=\frac {\sqrt {-b^{2} - \sqrt {a b} b} \arctan \left (\frac {\cos \left (d x + c\right )}{d \sqrt {-\frac {b d^{2} + \sqrt {{\left (a - b\right )} b d^{4} + b^{2} d^{4}}}{b d^{4}}}}\right )}{2 \, {\left (b + \sqrt {a b}\right )} d {\left | b \right |}} + \frac {\sqrt {-b^{2} + \sqrt {a b} b} \arctan \left (\frac {\cos \left (d x + c\right )}{d \sqrt {-\frac {b d^{2} - \sqrt {{\left (a - b\right )} b d^{4} + b^{2} d^{4}}}{b d^{4}}}}\right )}{2 \, {\left (b - \sqrt {a b}\right )} d {\left | b \right |}} \]
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Time = 0.52 (sec) , antiderivative size = 976, normalized size of antiderivative = 8.49 \[ \int \frac {\sin ^3(c+d x)}{a-b \sin ^4(c+d x)} \, dx=\frac {2\,\mathrm {atanh}\left (\frac {8\,a\,b^2\,\cos \left (c+d\,x\right )\,\sqrt {\frac {\sqrt {a\,b^3}}{16\,\left (a\,b^3-b^4\right )}-\frac {b^2}{16\,\left (a\,b^3-b^4\right )}}}{2\,a\,b+\frac {2\,a\,b^5}{a\,b^3-b^4}-\frac {2\,a\,b^3\,\sqrt {a\,b^3}}{a\,b^3-b^4}}-\frac {8\,a\,b^6\,\cos \left (c+d\,x\right )\,\sqrt {\frac {\sqrt {a\,b^3}}{16\,\left (a\,b^3-b^4\right )}-\frac {b^2}{16\,\left (a\,b^3-b^4\right )}}}{2\,a\,b^5-2\,a^2\,b^4-\frac {2\,a^2\,b^8}{a\,b^3-b^4}+\frac {2\,a\,b^9}{a\,b^3-b^4}+\frac {2\,a^2\,b^6\,\sqrt {a\,b^3}}{a\,b^3-b^4}-\frac {2\,a\,b^7\,\sqrt {a\,b^3}}{a\,b^3-b^4}}+\frac {8\,a\,b^4\,\cos \left (c+d\,x\right )\,\sqrt {a\,b^3}\,\sqrt {\frac {\sqrt {a\,b^3}}{16\,\left (a\,b^3-b^4\right )}-\frac {b^2}{16\,\left (a\,b^3-b^4\right )}}}{2\,a\,b^5-2\,a^2\,b^4-\frac {2\,a^2\,b^8}{a\,b^3-b^4}+\frac {2\,a\,b^9}{a\,b^3-b^4}+\frac {2\,a^2\,b^6\,\sqrt {a\,b^3}}{a\,b^3-b^4}-\frac {2\,a\,b^7\,\sqrt {a\,b^3}}{a\,b^3-b^4}}\right )\,\sqrt {-\frac {b^2-\sqrt {a\,b^3}}{16\,\left (a\,b^3-b^4\right )}}}{d}-\frac {2\,\mathrm {atanh}\left (\frac {8\,a\,b^6\,\cos \left (c+d\,x\right )\,\sqrt {-\frac {b^2}{16\,\left (a\,b^3-b^4\right )}-\frac {\sqrt {a\,b^3}}{16\,\left (a\,b^3-b^4\right )}}}{2\,a\,b^5-2\,a^2\,b^4-\frac {2\,a^2\,b^8}{a\,b^3-b^4}+\frac {2\,a\,b^9}{a\,b^3-b^4}-\frac {2\,a^2\,b^6\,\sqrt {a\,b^3}}{a\,b^3-b^4}+\frac {2\,a\,b^7\,\sqrt {a\,b^3}}{a\,b^3-b^4}}-\frac {8\,a\,b^2\,\cos \left (c+d\,x\right )\,\sqrt {-\frac {b^2}{16\,\left (a\,b^3-b^4\right )}-\frac {\sqrt {a\,b^3}}{16\,\left (a\,b^3-b^4\right )}}}{2\,a\,b+\frac {2\,a\,b^5}{a\,b^3-b^4}+\frac {2\,a\,b^3\,\sqrt {a\,b^3}}{a\,b^3-b^4}}+\frac {8\,a\,b^4\,\cos \left (c+d\,x\right )\,\sqrt {a\,b^3}\,\sqrt {-\frac {b^2}{16\,\left (a\,b^3-b^4\right )}-\frac {\sqrt {a\,b^3}}{16\,\left (a\,b^3-b^4\right )}}}{2\,a\,b^5-2\,a^2\,b^4-\frac {2\,a^2\,b^8}{a\,b^3-b^4}+\frac {2\,a\,b^9}{a\,b^3-b^4}-\frac {2\,a^2\,b^6\,\sqrt {a\,b^3}}{a\,b^3-b^4}+\frac {2\,a\,b^7\,\sqrt {a\,b^3}}{a\,b^3-b^4}}\right )\,\sqrt {-\frac {b^2+\sqrt {a\,b^3}}{16\,\left (a\,b^3-b^4\right )}}}{d} \]
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